Here are the basic logarithm laws - quite handy for simplifying complex calculations

May 18, 2025


  • Product Rule:
    The logarithm of a product is the sum of the logarithms of the individual factors.

  • Quotient Rule: The logarithm of a quotient is the difference between the logarithm of the numerator and the logarithm of the denominator.

  • Power Rule: The logarithm of a number raised to a power is the product of the power and the logarithm of the number.

  • Change of Base Rule: This rule allows you to convert logarithms from one base to another.

  • Logarithm of the Base: The logarithm of the base to itself is always 1.

  • Logarithm of One: The logarithm of 1 to any base is always 0.


මූලික භින්න භාග ආකාර

May 18, 2025

 

1. හරයේ ඒකජ සාධක ඇති විට
2. හරය පුනරාවර්තන ඒකජ සාධක ඇති විට
3. හරය ඒකජ නොවන සාධක ඇති විට
4. හරයේ මාත්‍රය ළවේ මාත්‍රයට සමානවිට
5.ලවයේ මාත්‍රය හරයේ මාත්‍රයට වඩා එකකින්  විශාල විට

බහු පද ශ්‍රිත - බෙදුම් ඇල්ගොරිතමය - ශේෂ ප්‍රමේය - සාධක ප්‍රමේය

May 18, 2025
  • බෙදුම් ඇල්ගොරිතමය


භාජ්‍ය =භාජකය* ලබ්ධිය +ශේෂය
  • ශේෂ ප්‍රමේය


F(x) යන x හි බහු පද ශ්‍රිතය (x-a) නම් ඒකජ ශ්‍රිතයෙන් බෙදූවිට ලැබෙන ශේෂය F(a) වේ. 
  • සාධක ප්‍රමේය


F(x) යන x හි බහු පද ශ්‍රිතය (x-a) නම් ඒකජ ශ්‍රිතයෙන් බෙදූවිට ලැබෙන ශේෂය ශූන්‍ය නම් (x-a) යනු F(x) හි සාධකයකි.

How to Calculate the square root 3 using logarithms.

May 17, 2025

To find the square root of 3 using logarithms, you can use the property that log(a^b) = b * log(a). First, set the problem as finding x where x = √3. Taking the logarithm of both sides gives log(x) = log(√3). Since a square root is the same as raising to the power of 1/2, we can write this as log(x) = log(3^(1/2)). Applying the logarithmic power rule, this simplifies to log(x) = (1/2) * log(3). You would then find the value of log(3) (using a calculator or log table), multiply that value by 0.5, which gives you the logarithm of your answer. Finally, to find the actual value of √3, you would compute the antilogarithm (or inverse logarithm) of the result obtained in the previous step.







Most common vocabulary list of English - THE TEACHER’S WORD BOOK OF 30,000 WORDS

May 15, 2025

 

The Teacher’s Word Book of 30,000 Words, compiled by Edward L. Thorndike and published in 1932, is a foundational resource in the field of English language education and vocabulary studies. Designed to help educators focus on the most commonly used words in English, the book provides a ranked list of 30,000 words based on their frequency of use in literature, newspapers, and other written texts of the time. This list aimed to guide teachers in selecting vocabulary that would be most beneficial for students to learn, ensuring that language instruction was both practical and efficient. The word book was groundbreaking in its systematic, data-driven approach and laid the groundwork for future research in vocabulary acquisition and curriculum design. Despite its age, the book remains an important historical reference in linguistic studies and continues to influence modern approaches to language teaching and lexical analysis.

How to Prove 1+cot^2(theta)=cosec^2(theta)

May 15, 2025

  



Use the Pythagorean identity:

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1see how to prove it

Divide both sides of the identity by sin2(θ)

sin2(θ)sin2(θ)+cos2(θ)sin2(θ)=1sin2(θ) 

Final Answer:

1 + cot2(θ)
=cosec2(θ)

This proves the identity.



How to Prove tan^2(theta) +1=sec^2(theta)

May 15, 2025

 


Use the basic identity

sin2(θ)+cos2(θ)=1

\sin^2(\theta) + \cos^2(\theta) = 1

Divide both sides of the identity by cos2(θ)\cos^2(\theta)

sin2(θ)cos2(θ)+cos2(θ)cos2(θ)=1cos2(θ)\frac{\sin^2(\theta)}{\cos^2(\theta)} + \frac{\cos^2(\theta)}{\cos^2(\theta)} = \frac{1}{\cos^2(\theta)} tan2(θ)+1=sec2(θ)\tan^2(\theta) + 1 = \sec^2(\theta)

Final Answer:

tan2(θ)+1=sec2(θ)\boxed{\tan^2(\theta) + 1 = \sec^2(\theta)}

This proves the identity.




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